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x^2+2=-4x^2
We move all terms to the left:
x^2+2-(-4x^2)=0
We get rid of parentheses
x^2+4x^2+2=0
We add all the numbers together, and all the variables
5x^2+2=0
a = 5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·5·2
Δ = -40
Delta is less than zero, so there is no solution for the equation
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